(3p^2-q^2)-(4p^2-7q^2)=

Solution for (3p^2-q^2)-(4p^2-7q^2)= equation:

Simplifying
(3p2 + -1q2) + -1(4p2 + -7q2) = 0

Remove parenthesis around (3p2 + -1q2)
3p2 + -1q2 + -1(4p2 + -7q2) = 0
3p2 + -1q2 + (4p2 * -1 + -7q2 * -1) = 0
3p2 + -1q2 + (-4p2 + 7q2) = 0

Reorder the terms:
3p2 + -4p2 + -1q2 + 7q2 = 0

Combine like terms: 3p2 + -4p2 = -1p2
-1p2 + -1q2 + 7q2 = 0

Combine like terms: -1q2 + 7q2 = 6q2
-1p2 + 6q2 = 0

Solving
-1p2 + 6q2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-6q2' to each side of the equation.
-1p2 + 6q2 + -6q2 = 0 + -6q2

Combine like terms: 6q2 + -6q2 = 0
-1p2 + 0 = 0 + -6q2
-1p2 = 0 + -6q2
Remove the zero:
-1p2 = -6q2

Divide each side by '-1'.
p2 = 6q2

Simplifying
p2 = 6q2

Take the square root of each side:
p = {-2.449489743q, 2.449489743q}